sydneelittle3851 sydneelittle3851
  • 02-07-2018
  • Mathematics
contestada

Let the random variable x be equally likely to assume any of the values 1/12, 1/6, or 1/4. determine the mean and variance of x.

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 02-07-2018
The mean of x is
  (1/3)(1/12 + 1/6 + 1/4) = 1/6

The mean of the squares is
  (1/3)((1/12)² + (1/6)² + (1/4)²) = 7/216

The variance is the difference between the mean square and the square of the mean.
  7/216 -(1/6)² = 1/216

The mean of x is 1/6.
The variance of x is 1/216.
Answer Link

Otras preguntas

What is the value of (1/8)^-1/3PLEASE I NEED THE AWNSER QUICK PLEASE AND TY
Discuss the ways to divide up the nervous system noting what helps regulate what functions
In trapezoid ABCD, Line AB is parallel to CD. If AE=5.2, AC=11.7 and CD=10.5, what is the length of AB to the nearest tenth?
Find the product using Distributive property. 625 x 129 – 625 x 90​
Complete the balanced neutralization equation for the reaction below: HNO3(aq) + Ba(OH)2(aq) →
Ever wondered what drives humans to explore space? What is it we seek? I believe we are driven by the desire to be the first to explore, conquer, and own newly
how can geo thermal energy be used ?​
50 Points will mark Brainliest What is the circumference of circle P? Express your answer in terms of π. 34π cm 68π cm 17π cm 58π cm
What is 3x(2 3/4) simplify my
I get the part A of the question its just the part B that i would really appreciate for someone to explain