katbuford
katbuford katbuford
  • 02-04-2016
  • Mathematics
contestada

i understand some of this but this ones got me stumped i tried pemdas but im still lost

i understand some of this but this ones got me stumped i tried pemdas but im still lost class=

Respuesta :

lukyo
lukyo lukyo
  • 03-04-2016
Just replace [tex]x[/tex] with its given value:

[tex]9x^{2}-4x-3~~~~\text{where }x=-2\\ \\ \\ 9\cdot (-2)^{2}-4\cdot (-2)-3\\ \\ =9\cdot 4+8-3\\ \\ =36+8-3\\ \\ =41[/tex]
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