JWHARMAN
JWHARMAN JWHARMAN
  • 03-01-2019
  • Mathematics
contestada

Solve on the interval 0 2pi. 2sec(x)+6=2

Respuesta :

jimrgrant1 jimrgrant1
  • 03-01-2019

Answer:

x = [tex]\frac{2\pi }{3}[/tex], x = [tex]\frac{4\pi }{3}[/tex]

Step-by-step explanation:

using the trigonometric identity

• sec x = [tex]\frac{1}{cosx}[/tex]

isolate sec x by subtracting 6 from both sides and dividing both sides by 2

2sec x = - 4 ⇒ sec x = - 2, hence

[tex]\frac{1}{cosx}[/tex] = - 2

⇔ cosx = - [tex]\frac{1}{2}[/tex]

since cos x < 0 then x is in second/ third quadrant

x = [tex]\frac{2\pi }{3}[/tex] or x = [tex]\frac{4\pi }{3}[/tex]



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