bm42400
bm42400 bm42400
  • 03-05-2019
  • Mathematics
contestada

Please select the best answer from the choices provided

Please select the best answer from the choices provided class=

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 03-05-2019

Answer:

[tex]x=\frac{5\pi}{4}[/tex]

Step-by-step explanation:

We want to solve;

[tex]\cscx=-\sqrt{2}[/tex] in the 3rd quadrant

Recall that;

[tex]\sin x=\frac{1}{\csc x}[/tex]

We use the reciprocal ratio to get;

[tex]\sin x=-\frac{\sqrt{2}}{2}[/tex]

In the third quadrant the solution is

[tex]x=\pi+\sin^{-1}(\frac{\sqrt{2} }{2} )[/tex]

[tex]x=\pi+\frac{\pi}{4}[/tex]

[tex]x=\frac{5\pi}{4}[/tex]

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