rianisaghost rianisaghost
  • 01-10-2019
  • Mathematics
contestada

whats the answer to that

whats the answer to that class=

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Аноним Аноним
  • 01-10-2019

Given a quadratic equation

[tex]ax^2+bx+c=0[/tex]

The solutions are given by

[tex]\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In your case,

[tex]a=1,\quad b=3,\quad c=1[/tex]

So, the solutions are

[tex]\dfrac{-3\pm\sqrt{9-4}}{2}=\dfrac{-3\pm\sqrt{5}}{2}[/tex]

So, the two solutions are

[tex]x_1 = \dfrac{-3+\sqrt{5}}{2},\quad x_2=\dfrac{-3-\sqrt{5}}{2}[/tex]

And they are approximated by

[tex]x_1\approx -0.38,\quad x_2\approx -2.62[/tex]

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