adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

Pls someone help me with thissss plsss
Solve for j. 24 = 6j
armando save 30% of his monthly paycheck for college he are in $450 last month how much money did armando save for college
The correct order of the process that occurs when a sperm encounters an egg is the a. sperm reaches ovum, zona pellucida dissolves, zygote is formed, implantati
Please help!!! Make up a word problem that the following equation could represent: 5x + 9 = 44
divide 3,000 yards by 1,760
What is Z? ⅓ (z + 4) - 6 = ⅔ (5 - z)
Imagine you are an entrepreneur starting a new video game company. What kind of financing would you most likely use to test out your new business idea? A. Debt
What are some possible themes for Ray Bradbury's "Zero Hour"?
Find the value of x. Round your answer to the nearest tenth.