Respuesta :

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=2\\ h=5 \end{cases}\implies V=\cfrac{\pi (2)^2(5)}{3} \\\\\\ V=\cfrac{20\pi }{3}\implies V\approx 20.94[/tex]