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01-12-2019
Chemistry

contestada

determine the h+ of 0.005 KOH

Respuesta :

13-12-2019

Answer:

[H⁺] = 2.0 × 10⁻¹² M

Explanation:

Given data:

Concentration of KOH = 0.005M

H⁺ = ?

Solution:

pOH = -log[ OH⁻]

pOH = -log[0.005]

pOH = 2.3

pH + pOH = 14

14 - pOH = pH

pH = 14 - 2.3

pH = 11.7

pH = -log[H⁺]

11.7 = -log[H⁺]

[H⁺] = Antilog (-11.7)

[H⁺] = 2.0 × 10⁻¹² M

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