drrj2x drrj2x
  • 03-12-2019
  • Mathematics
contestada

If f(x)=2x^6+x^5+32x+32, is (x+2) a factor of f(x).

Respuesta :

jimrgrant1 jimrgrant1
  • 03-12-2019

Answer:

No

Step-by-step explanation:

By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2[tex](-2)^{6}[/tex] + [tex]-2)^{5}[/tex] + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

Answer Link
bezgodovdaniella
bezgodovdaniella bezgodovdaniella
  • 16-05-2020

Answer: By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2(-2)^{6} + -2)^{5} + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

Answer Link

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