alinateow
alinateow alinateow
  • 01-02-2020
  • Mathematics
contestada

hi ! How to solve this question?

hi How to solve this question class=

Respuesta :

LammettHash
LammettHash LammettHash
  • 01-02-2020

You should actually have

[tex]-x^2-4x-10=-(x^2+4x+10)=-(x^2+4x+4+6)=-((x+2)^2+6)=-(x+2)^2-6[/tex]

Now, remember that [tex]x^2[/tex] is always non-negative, so [tex](x+2)^2\ge0[/tex] for any value of [tex]x[/tex]. This means [tex]-(x+2)^2\le0[/tex] for any [tex]x[/tex], and so

[tex]-(x+2)^2-6\le0-6=-6[/tex]

i.e. f(x) is at most -6, and hence negative for all [tex]x[/tex].

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