iiiMann
iiiMann iiiMann
  • 01-04-2020
  • Mathematics
contestada

Please Help! It is Pre-Calc and I need to know the answer!

Please Help It is PreCalc and I need to know the answer class=

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DeanR
DeanR DeanR
  • 01-04-2020

That's the derivative at 2 so is going to be 2(2)+1=5, second choice, but let's do it the hard way.

[tex]\displaystyle \lim_{h \to 0} \dfrac{f(2+h)-f(2)}{h} = \lim_{h \to 0} \dfrac{(2+h)^2 + (2+h) + 1 -(2^2 + 2 + 1)}{h}[/tex]

[tex]\displaystyle =\lim_{h \to 0} \dfrac{4 + 4h +h^2 +h-4}{h}=\lim_{h \to 0} \dfrac{h^2 +5h}{h} = \lim_{h \to 0} h+5 = 5[/tex]

Answer: 5, second choice

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