lawrencesabrina015 lawrencesabrina015
  • 01-06-2020
  • Mathematics
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Instructions : integrate the following

Instructions integrate the following class=

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LammettHash
LammettHash LammettHash
  • 01-06-2020

You can simplify the integrand:

[tex]\dfrac{3x^2+4x+1}{2x}=\dfrac{3x}2+2+\dfrac1{2x}[/tex]

Then integrate term-by-term:

[tex]\displaystyle\int\frac{3x^2+4x+1}{2x}\,\mathrm dx=\frac32\int x\,\mathrm dx+2\int\mathrm dx+\frac12\int\frac{\mathrm dx}x[/tex]

[tex]=\dfrac{3x^2}4+2x+\dfrac12\ln|x|+C[/tex]

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