dss354201
dss354201 dss354201
  • 03-06-2020
  • Mathematics
contestada

how would you solve 4x - 3y = 78 2x + 3y = 48 by elimination

Respuesta :

Hrishii
Hrishii Hrishii
  • 03-06-2020

Answer:

x = 21, y = 2

Step-by-step explanation:

4x- 3y = 78....(1)

2x + 3y = 48 ...(2)

Adding eqiautions (1) and (2)

4x- 3y = 78

2x + 3y = 48

-----------------------

6x + 0 = 126....(Here y has been eliminated)

6x = 126

[tex] x= \frac{126}{6}\\\\

\therefore x = 21\\[/tex]

Plugging x = 21 in equation (2) we find:

2 * 21 + 3y = 48

42 + 3y = 48

3y = 48 - 42

3y = 6

[tex] y= \frac{6}{3}\\\\

\therefore y = 2\\[/tex]

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