tobiascitlaly6777 tobiascitlaly6777
  • 04-07-2020
  • Mathematics
contestada

1) sqrt x^+6x+9 if x≥3
2) sqrt x^2+6x+9 if −3≤x<3
3) sqrt x^2−6x+9 if x<−3
will give brainliest

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mani82ebra
mani82ebra mani82ebra
  • 04-07-2020

Answer:

Step-by-step explanation:

first one:

[tex]x^{2}+6x+9={(x+3)}^{2} \\\sqrt{{(x+3)}^{2} }=x+3[/tex]

second one:

[tex]x^{2}+6x+9=(x+3)^{2} \\\sqrt{(x+3)^{2} } = x+3[/tex]

third one:

[tex]x^{2} -6x+9=(x-3)^{2} \\\sqrt{(x-3)^{2} } =|x-3| \ \ (because \ x<-3)[/tex]

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