rodrihc rodrihc
  • 03-08-2020
  • Mathematics
contestada

2x.tg60= 10+csc30 plis

Respuesta :

mirai123
mirai123 mirai123
  • 03-08-2020

Answer:

[tex]2\sqrt{3}[/tex]

Step-by-step explanation:

I'm assuming the angles are in degrees.

[tex]2x \tan(60\º)=10+\csc(30\º)[/tex]

[tex]$2x\cdot \sqrt{3}=10+\frac{1}{\sin(30\º)} $[/tex]

[tex]$2x\cdot \sqrt{3}=10+\frac{1}{\frac{1}{2} } $[/tex]

[tex]$2x\cdot \sqrt{3}=10+2} $[/tex]

[tex]$x=\frac{12}{2\sqrt{3}} $[/tex]

[tex]$x=\frac{6}{\sqrt{3}} =\frac{6\sqrt{3}} {3} }=2\sqrt{3} $[/tex]

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