Ni2+(aq) + SO42–(aq) + 2Na+(aq) + S2–(aq) NiS(s) + 2Na+(aq) + SO42–(aq) net ionic equation ?

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03-10-2020
Chemistry

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Ni2+(aq) + SO42–(aq) + 2Na+(aq) + S2–(aq) NiS(s) + 2Na+(aq) + SO42–(aq) net ionic equation ?

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JazzyHorn JazzyHorn · Answer 1 · 2020-10-03T16:31:54+02:00

To get the net Ionic equation we must get rid of spectator ions, I.E. the ions that repeat on either side of the equation.

So...!

[tex]Ni_{2}[/tex][tex](aq)^{+}[/tex] + [tex]SO_{4}(aq)^2-[/tex] + [tex]2Na(aq)^+[/tex] + [tex]S_{2} (aq)^{2} -[/tex] → [tex]2NiS(s)[/tex] + [tex]2Na(aq)^{+}[/tex] + [tex]SO_{4}(aq)^{2-}[/tex]

This becomes the following net ionic.

[tex]Ni_{2}[/tex][tex](aq)^{+}[/tex] + [tex]S_{2} (aq)^{2} -[/tex] → [tex]2NiS(s)[/tex]