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  • 01-09-2021
  • Mathematics
contestada

c(ge + p) = n +j

Solve for c: C=​

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Аноним Аноним
  • 01-09-2021

Answer:

[tex]c(ge + p) = n + j \\ \\ \frac{c(ge + p)}{(ge + p)} = \frac{n + j}{(ge + p)} \\ \\ { \boxed{ \boxed{c = \frac{n + j}{ge + p} }}}[/tex]

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