haileyulloa15 haileyulloa15

04-05-2022
Mathematics

contestada

Please help.... this is confusing me:0

Please help this is confusing me0 class=

Respuesta :

jsimpson11000 jsimpson11000

04-05-2022

Answer:

See below

Step-by-step explanation:

IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!

sin z = O/H = opposite side/hypotenuse = 16/20

cos z = A/H = adjacent / hy[potenuse = 12/20

tan z = O/A = 16/12

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