RusselD248291 RusselD248291
  • 03-11-2022
  • Mathematics
contestada

Suppose that a variable has a binomial distribution with n=18 and p=0.48 what is the expected value of the variable?

Suppose that a variable has a binomial distribution with n18 and p048 what is the expected value of the variable class=

Respuesta :

NishaanS197970 NishaanS197970
  • 03-11-2022

Answer:

8.64

Explanation:

The expected value for a binomial distribution is equal to

E = np

Where n is the number of trials and p is the probability of success. In this case, n = 18 and p = 0.48. Then, the expected value is

E = (18)(0.48)

E = 8.64

Therefore, the answer is 8.64

Answer Link

Otras preguntas

Need help with 4,5,6 please
do the right thing what type of sentence is it
52,789 rounded to nearest thousand
Why are perfect squares not prime numbers?
mystery number 1 here are your Clues I called this a level 1 first clue I am a 2 digit number second clue my tens digit is a multiply of my ones digit third clu
PLEASE HELP !!!! What is the slope of the line passing through the points (1, −5)(1, −5) and (4, 1)(4, 1)?
Is magnesium a positive or negative ion
Any help please I really can't figure this out
How should you use transitions within your paper?
Which of these is an effective way of guiding, modifying, and disciplining a child? A. Gerard praises the child even when he makes a mistake. B. Sean sets clea