KadianR676250 KadianR676250
  • 03-11-2022
  • Mathematics
contestada

Hii I really need help right now I don’t understand.

Hii I really need help right now I dont understand class=

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MykaiE146134 MykaiE146134
  • 03-11-2022

The function is given as,

[tex]y=4^x[/tex]

For x = -1 , the value of y is calculated as,

[tex]\begin{gathered} y=4^{-1} \\ y\text{ = }\frac{1}{4} \\ y\text{ = 0.25} \end{gathered}[/tex]

For x = 0 , the value of y is calculated as,

[tex]\begin{gathered} y=4^0 \\ y\text{ = 1} \end{gathered}[/tex]

For x = 1 , the value of y is calculated as,

[tex]\begin{gathered} y=4^1 \\ y\text{ = 4} \end{gathered}[/tex]

For x = 2, the value of y is calculated as,

[tex]\begin{gathered} y=4^2 \\ y\text{ = 16} \end{gathered}[/tex]

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