CadienD502315 CadienD502315
  • 03-11-2022
  • Mathematics
contestada

Number 9, Im not quite sure on how to do these

Number 9 Im not quite sure on how to do these class=

Respuesta :

TaleahP36706 TaleahP36706
  • 03-11-2022

Solution:

Given:

[tex]f(x)=2(x-3)^2+1[/tex]

The equation of a parabola in vertex form is given by:

[tex]y=a(x-h)^2+k[/tex]

The coordinates of the vertex is given by (h,k).

Hence, comparing both equations,

[tex]\begin{gathered} f(x)=2(x-3)^2+1 \\ y=a(x-h)^2+k \\ a=2 \\ h=3 \\ k=1 \end{gathered}[/tex]

Therefore, the coordinates of the vertex is;

[tex](h,k)=(3,1)[/tex]

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