mellinag mellinag

04-09-2017
Mathematics

contestada

m is the midpoint of segment AB. AM=2x^2+16, AB=6x^2. Find AB

Respuesta :

kphung76127 kphung76127

04-09-2017

If M is the midpoint, 2 times AM should be equal to AB

2(2x^2+16)=6x^2
4x^2+32=6x^2
32= 2x^2
16=x^2
4=x

Now plug the value of x in
6(4)^2
6*16
96

Final answer: 96

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