A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2.5m on the floor. calculate the coefficient of sliding friction [g = 10.0 ms per second per second]
You have to solve this by using the equations of motion: u=3 v=0 s=2.5 a=? v^2=u^2+2as 0=9+5s Giving a=-1.8m/s^2
Then using the equation: F=ma F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.
-F=25(-1.8) F=45N
Then use the formula: F=uR Where u is the coefficient of friction, R is the normal force and F is the frictional force.
