musicnotesloves
musicnotesloves musicnotesloves
  • 03-06-2018
  • Mathematics
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in the diagram, m <ACB =66 find M <BCD

in the diagram m ltACB 66 find M ltBCD class=

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izdoctor23773
izdoctor23773 izdoctor23773
  • 03-06-2018
Alrighty. If there's 3 angles that are on one linear line, they all must add up to 180, because they would wall be supplementary angles (they all add up to 180).

So, we know that the Angle FCA is 90 degrees, and we know that ACB is 66 since they said so. So, we will add them up, then subtract it from 180. So,

BCD + 66 + 90 = 180
BCD + 156 = 180
BCD = 24

(P.S, that means the angle FCE will be the same because of vertical angle theorem)
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