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solve for x in the equation 2x2-5x+1=3

A. x=5/2 +/- square root of 29/2

B. x=5/2 +/- square root of 41|
s4

C. x= 5/4 +/- square root of 29/2

D. x= 5/4 +/- square root of 41/4

Respuesta :

claudettoterohil
2x^2 - 5x + 1 = 3

Subtract 3 from both sides
2x^2 - 5x + 1  - 3 = 3  - 3

2x^2 - 5x - 2 = 0

Use quadratic formula with A = 2,  B =  - 5,   C =  - 2

x =  - b +- sqrt b^2 - 4ac/2a

x =  - ( - 5) +- sqrt (- 5)^2  - 4(2)( - 2)/(2)(2)

x =   5 +- sqrt 41/4

x =  5/4 + 1/4sqrt 41  or x = 5/4 + - 1/4 sqrt 41


Answer:  x = 5/4 + 1/4 sqrt 41
               x = 5/4 +  - 1/4 sqrt 41




Hope that helps!!!!! (D)

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