Respuesta :

calculista

we know that


1) PD=PB= radius of the circle P


2) initially PDB is an isosceles triangle. because has two sides equals

so

m ∠ DBP=m ∠ PDB

m ∠ DBP+m ∠ PDB+m ∠ DPB=180

m ∠ DBP=[180-60]/2------> m ∠ DBP=60


3) if m ∠ DBP=60°

then

the 3 angles are equals

PDB is an equilateral triangle


therefore


the answer is

m ∠ DBP=60°

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