nicknicknick5550 nicknicknick5550
  • 02-08-2018
  • Mathematics
contestada

Identify the equation of the circle that has its center at (10, 24) and passes through the origin.

Respuesta :

rejkjavik rejkjavik
  • 02-08-2018

we are given

center=(h,k)=(10,24)

so,

h=10 and k=24

and it passes through origin

so, we can find radius

radius will be distance between (10,24) and (0,0)

[tex] r=\sqrt{(10-0)^2+(24-0)^2} [/tex]

[tex] r=26 [/tex]

now, we can use standard equation of circle

[tex] (x-h)^2+(y-k)^2=r^2 [/tex]

so, we will get equation as

[tex] (x-10)^2+(y-24)^2=26^2 [/tex]..........Answer

Answer Link
ellispark795 ellispark795
  • 18-08-2022

Answer: (x−10)2+(y−24)2=676

Step-by-step explanation: it is right

Answer Link

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