jemamunoz1 jemamunoz1
  • 01-11-2018
  • Mathematics
contestada

Identify the focus, directrix, and axis of symmetry of 11x=y^2

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tramserran
tramserran tramserran
  • 02-11-2018

Answers

focus: (0, [tex]\frac{11}{4}[/tex])

directrix: x = [tex]-\frac{11}{4}[/tex]

AOS: y = 0

Step-by-step explanation:

11x = y²

 x = [tex]\frac{1}{11}[/tex]y²

 x = [tex]\frac{1}{11}[/tex](y - 0)² + 0

Vertex: (0, 0)

Axis of symmetry: y = 0

Focus: [tex]\frac{1}{4p} = a[/tex]     a = [tex]\frac{1}{11}[/tex]

[tex]\frac{1}{4p} = \frac{1}{11}[/tex]

4p = 11

 p = [tex]\frac{11}{4}[/tex] so, focus is: (0, [tex]\frac{11}{4}[/tex])

Directrix: -p = [tex]-\frac{11}{4}[/tex] so, directrix is: x = [tex]-\frac{11}{4}[/tex]




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