Seudónimo Seudónimo
  • 02-12-2018
  • Mathematics
contestada

what is the area of the irregular pentagon

a. 43


b. 105



C)

108 in2



D)

114 in2

what is the area of the irregular pentagon a 43 b 105C 108 in2 D 114 in2 class=

Respuesta :

Asgardian Asgardian
  • 13-12-2018

Answer:

Answer  is 105 in^2

Step-by-step explanation:   Area of rectangle= length X breadth

= 8X12

=96in^ 2

Area of triangle= 1/2 X  base X height

= 1/2 X 3 X 6

= 9 in^2

Area of irregular pentagon = area of triangle + area of rectangle

= 96+9

=105 in ^2


Answer Link
Аноним Аноним
  • 21-12-2018

Answer:

Answer  is 105 in^2

Step-by-step explanation:  

Area of rectangle= length X breadth = 8X12=96in^ 2Area of triangle= 1/2 X  base X height= 1/2 X 3 X 6= 9 in^2 Area of irregular pentagon = area of triangle + area of rectangle = 96+9=105 in ^2

Answer Link

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