KingofCupcakes153 KingofCupcakes153

04-04-2019
Mathematics

contestada

The vertices of triangle ABC are A(2,3), B(–1,2), and C(3,1). If ΔDEF ∼ ΔABC and DE = 4AB, what is the length of EF? The answers are √10,√17,4√10,4√17

Respuesta :

Dlalex2316 Dlalex2316

04-04-2019

EF = 4BC

BC = sqrt ((3-(-1)^2 +(1-2)^2)

=》 BC = sqrt (4^2 +(-1)^2) = sqrt17

=》 EF = 4BC = 4(sqrt 17)

Answer Link

simp4luffy simp4luffy

07-12-2020

Answer:

D. 4√17

Step-by-step explanation:

Answer Link

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