For this case we have a system of two equations with two unknowns:
[tex]x = -3y-13\\2x + 2y = -6[/tex]
To solve we follow the steps below:
We substitute the first equation in the second:
[tex]2 (-3y-13) + 2y = -6[/tex]
We apply distributive property to the terms of parentheses:
[tex]-6y-26 + 2y = -6[/tex]
We add 26 to both sides of the equation:
[tex]-6y + 2y = -6 + 26\\-4y = 20\\y = \frac {20} {- 4}\\y = -5[/tex]
We find the value of x:
[tex]x = -3 (-5) -13\\x = 15-13\\x = 2[/tex]
Answer:
[tex](x, y) :( 2, -5)[/tex]
