hinamibarden141 hinamibarden141
  • 02-09-2019
  • Physics
contestada

A child sits 1.6 m from the center of a merry go round that makes one complete revolution in 4.7 s. What is his angular acceleration?

Respuesta :

enyo enyo
  • 05-09-2019

Answer: angular acceleration = [tex]2.86\ rad/sec^{2}[/tex]

Given:

Distance from center of axis = 1.6 m

Time taken to complete one revolution = 4.7 sec

Therefore, we can evaluate the angular acceleration using the following formula:

[tex]\alpha = r\times \omega^{2}[/tex]

[tex]\alpha = r\times (\frac{2\pi}{T})^{2}[/tex]

[tex]\alpha = 1.6\times (\frac{2\times3.14}{4.7})^{2}[/tex]

[tex]\alpha[/tex] = [tex]2.86\ rad/sec^{2}[/tex]

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