trcop trcop
  • 03-09-2019
  • Mathematics
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Determine equation of the circle that contains the points (3, 2), (3, -6), (7, -2) and (-1, -2)

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jdoe0001 jdoe0001
  • 03-09-2019

Check the picture below.

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{3}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{4}{ r}\\[2em] [x-3]^2+[y-(-2)]^2=4^2\implies (x-3)^2+(y+2)^2=16[/tex]

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