HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

Suppose you have a job at a restaurant as a food runner making $12 per hour. You also have a job at a retail store selling shoes making $8.50 per hour. You aren
A trombone acts like an open pipe of length 2.96 m .On a cold day it plays,its 4th harmonic at 221 hz what is the speed of the sound waves in the horn that day?
Simplify the expression: 2(3 + g) =
Training in how to handle hazards such as utilities and Hazardous Materials (HazMat) should be provided to responders by the:
WIll give Brainliest if answered in 5 sentences) How was Europe a fertile environment for the rise of fascism in the early part of the 20th century?
When a force of 2.4 newtons is applied to a spring, the extension is 0.4 m. What is the spring constant? 6 N/m 9.6 N/m 2 N/m 2.4 N/m
Can someone help me with this.
The midpoint of AB is M (-1, -5). If the coordinates of A are (3, -8), what are the coordinates of B?
GIVING BRAINLY OUT FOR WHOEVER IS CORRECT AND FAST! The length of a rectangle is twice as long as it's width. The perimeter of this rectangle is how many times
simplify: 4 x - -5х + 3x- x+2х - 7х