jaydawg2145
jaydawg2145 jaydawg2145
  • 03-04-2020
  • Mathematics
contestada

Needs help asap pls :) ill give brainly to the first answer correct.

Needs help asap pls ill give brainly to the first answer correct class=

Respuesta :

s159783 s159783
  • 03-04-2020

Answer:

16 ; √16

Step-by-step explanation:

For the first one, (√ 16 )^2 = 4^2 = 16.

For the second one, (16^1/2)^2 = 16^1 or 16. Look at the previous statement. (√ 16)^2 is also equal to 16! So, based on transitive property (if a = b, and b = c, then a = c), 16^1/2 = √ 16!

Hope this helped!

Answer Link

Otras preguntas

What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm
What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm