kachek414 kachek414
  • 03-04-2020
  • Mathematics
contestada

I need the first six terms of an=(n+3)^2
PLease and thank you :)

Respuesta :

LuvEthann
LuvEthann LuvEthann
  • 03-04-2020
Sorry, I’m only in 6th Grade, I don’t know the answer.
Answer Link
ghanami
ghanami ghanami
  • 03-04-2020

Answer:

Step-by-step explanation:

hello :

the first six terms of an=(n+3)^2 are :

a1= (1+3)² = 4² = 16

a2= (2+3)² = 5²=25

a3= (3+3)²=6²=36

a4= (4+3)²=7²=49

a5= (5+3)²=8²=64

a6= (6+3)²=9²=81

Answer Link

Otras preguntas

what is the domain and range for y=lxl
true or false all whole numbers are integers
22.) -5n+3(6+7n) 23.) -2n-(9-10n) 24.) 10-5(9n-9)
Which mixed number is greater: 5 7/24 or 5 5/16? Why?
What equation in slope intercept form represents the line that passes through the two points 2,5 (9,2
g5-h3 if g=2 and h=7 solve expression
Explain why contact trace evidence is so important in solving crimes.
i need a paragraph on work experience like where i went ,what i did,what my boss was like and what i did during the work experience ? can anyone help?!
What is the value of (-4.5) (-8.25) ? Please!
g5-h3 if g=2 and h=7 solve expression