ooouulexi5581 ooouulexi5581
  • 04-06-2020
  • Mathematics
contestada

Find the sum of the geometric series 1 + 0.8 + 0.8^2 +0.8^3 + ... + 0.8^{19}

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 09-06-2020

Answer:

S20 ≈ 4.942

Step-by-step explanation:

Sum of a geometric series is expressed as Sn = a(1-rⁿ)/1-r if r<1

a is the first term

r is the common ratio

n is the number of terms

Given the geometric series

1 + 0.8 + 0.8^2 +0.8^3 + ... + 0.8^{19}

Given a = 1,

r = 0.8/1 = 0.8²/0.8 = 0.8

n = 20 (The total number of terms in the series is 20)

Substituting this values in the formula above.

S20 = 1(1-0.8^20)/1-0.8

S20 = 1-0.01153/0.2

S20 = 0.9885/0.2

S20 ≈ 4.942

Answer Link

Otras preguntas

Canada and the US celebrate Labour Day the first Monday of September. Many other countries honour workers with International Workers' Day. When is that celeb
Keisha's parents want to save twenty thousand dollars in her college savings account over the next fifteen years. They have eight thousand dollars to use as an
What value is the 9s in 299?
Mrs Frazier is making costumes for the school play. Each costume requires 0.75 yards of fabric. She bought 6 yards of fabric. How many costumes can Mrs Frazier
I don't get exponents
Which of the following best describes Daniel Webster’s views? a. .he disagreed with slavery but supported compromise b. he declared nullification a form of trea
Elevation refers to the ?
how to right 0.632 in expanded form
Differentiate between pseudoscience and science
What is the Noble gas notation of silicon (Si)? [Ne] 2s22p2 [Ar] 3s23p2 [Ne] 3s23p2 [Mg] 3p2?