ellie5935 ellie5935

04-08-2020
Mathematics

contestada

can someone explain mean and median to me?

Respuesta :

emadn23 emadn23

04-08-2020

Answer:

Mean is obtained by adding of all of the term values by the number of terms in a given set of data. Mean is also called "average".

Median on the other hand is the arrangement of numerical data in chronological order from least to greatest and finding the middle number from that arranged set of data.

Answer Link

Otras preguntas

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

find the circumference of a circle whose radius is 15.4cm

What value of x makes the equation true ? 4(2x-4)=16

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})