skye2736
skye2736 skye2736
  • 02-09-2020
  • Mathematics
contestada

Solve for a. 3x=a+3/b

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unicorn3125
unicorn3125 unicorn3125
  • 03-09-2020

[tex]3x=a+\frac3b\\\\-\frac3b\quad\ -\frac3b\\\\3x-\frac3b=a\\\\a=3x-\frac3b[/tex]

or, if you mean  3x=(a+3)/b :

[tex]{}\ \ 3x=\dfrac{a+3}b\\\\\times b\quad\ \ \times b\\\\3bx=a+3\\\\-3\qquad-3\\\\3bx-3=a\\\\a=3bx-3[/tex]

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