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02-11-2016
Chemistry

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What is the empirical formula for a compound if a sample contains 3.72 g of P and 21.28 g of Cl?

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02-11-2016

Given 3.72 g of P and 21.28g of Cl, converting these to moles: ( 3.72 g P)(mol P/30.97 g P) = 0.12 mol P (21.28 g Cl)(mol Cl/35.45 g Cl) = 0.60 mol Cl P:Cl = 0.12/0.60, therefore P: Cl =1/5 Therefore, PCl5 hope it helps

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