kennethsangler kennethsangler
  • 03-04-2021
  • Mathematics
contestada

Show that solving the equation 3^2x=4 by taking common logarithms of both sides is equivalent to solving it by taking logarithms of base 3 of both sides.

Respuesta :

altavistard
altavistard altavistard
  • 03-04-2021

Answer:

Step-by-step explanation:

Case I:  use common logs:

 2x log 3 = log 4, or 2x(0.47712) = 0.60206

 Solving for x, we get 0.95424x = 0.60206, and then x = 0.60206/0.95424.

 x is then x = 0.631

Case II:  use logs to the base 3:

 2x (log to the base 3 of 3) = (log to the base 3 of 4)

 This simplifies to 2x(1) = 2x = (log 4)/log 3 = 1.262.  Finally, we divide this

 result by 2, obtaining x = 0.631

Answer Link

Otras preguntas

When the heir to the throne of Austria hungriawas assassinated in 1914 what country was blamed
The second trimester begins at a. three months. b. four months. c. six months. d. nine months.
These types of building blocks are an energy source. a. fats b. water c. vitamins d. minerals
Emily had 75 buttons. She gave 15 buttons to jake. What percentage of the buttons did Emily give to hair?
Is petrol a conductor or an insulator
The skeletal system provides structural support for the entire body. What makes bones strong enough to protect body tissue?
The reign of Alexander II came to an end in 1881 when he __________.
Given a force of 100 n and an acceleration of 10 m/s2 what is the mass
5+ 10 + 6x 1/10 + 7x1000 in decimal form.
What is the verb phrase? 'They can take the bus to school''