mountaink97
mountaink97 mountaink97
  • 03-06-2021
  • Mathematics
contestada

At what input value will the function f(x)=x-5+2 begin to have real outputs?
[tex]f(x)= \sqrt{x-5+2} [/tex]
​

Respuesta :

swim21 swim21
  • 03-06-2021

Answer:

3

Step-by-step explanation:

I believe the answer is 3. Based on what we know about square roots, the expression under the square root symbol must be at least zero for the output to be real.

So you have

[tex]x-5+2\geq 0[/tex]

Solving this gives you

[tex]x-3\geq 0\\x\geq 3[/tex]

Therefore, the function will begin to have real output at the input value of 3.

Hope this helped.

Answer Link
elsiemarielewis elsiemarielewis
  • 20-12-2021

Answer:

5

Step-by-step explanation:

x-5+2

5-5+2=0+2=2  that's a real answer so the answer is 5 :)

Answer Link

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