nunezamy8
nunezamy8 nunezamy8
  • 01-07-2021
  • Mathematics
contestada

how to solve for
LN and what are the variables

how to solve for LN and what are the variables class=

Respuesta :

SDCInfinity
SDCInfinity SDCInfinity
  • 01-07-2021

Answer:

v See below. v

Step-by-step explanation:

LM = MN

11x - 21 = 8x + 15

[tex]3x-21=15\\3x=36\\[/tex]

x = 12

LM = 11(12) - 21 = 132 - 21 = 111

MN = 8(12) + 15 = 96 + 15 = 111

LN = 111 + 111 = 222

Answer Link

Otras preguntas

jasmines cd collection is 3/8 jazz 1/4 rap and the rest is rock music what is the fraction of rock music
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
find the circumference of a circle whose radius is 15.4cm
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
What value of x makes the equation true ? 4(2x-4)=16
In scientific notation, what is the sum of 2.3 times 10^{-3} and 5.4 times 10^{-4}?a. 2.84 times 10^{-3}b. 5.63 times 10^{-3}c. 7.7 times 10^{-7}d. 12.42 times
find the circumference of a circle whose radius is 15.4cm
All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})
find the circumference of a circle whose radius is 15.4cm
find the circumference of a circle whose radius is 15.4cm