LandriQ330978 LandriQ330978
  • 03-11-2022
  • Mathematics
contestada

h(-3) = 5(-3)^4 +7(-3)^3-4(-3)+3

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AmritaS574902 AmritaS574902
  • 03-11-2022

so we need to solve:

[tex]h(-3)=5\cdot(-3)^4+7\cdot(-3)^3-4\cdot(-3)+3[/tex]

first, let's solve the exponential (remember if the number is odd, the result of the exponential is negative because of the -3)

[tex]h(-3)=5\cdot81+7\cdot(-27)-4\cdot(-3)+3[/tex]

now the multiplications

[tex]\begin{gathered} h(-3)=405-189+12+3 \\ \text{note: negative}\cdot negative=positive \\ \text{negative }\cdot\text{ positive= negative} \end{gathered}[/tex]

and finally the sum.

and the answer is:

[tex]h(-3)=231[/tex]

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