Respuesta :

Answer:

0.53L

Explanations:

According to dilution formula:

[tex]C_1V_1=C_2V_2[/tex]

C1 and C2 are the initial and final concentrations

V1 and V2 is initial and final volume

Given the following parameters

• V1 = 45mL

,

• C2 = 0.2M

,

• V2 = 119.4mL

Substitute the given parameters into the formula

[tex]\begin{gathered} C_1=\frac{C_2V_2}{V_1} \\ C_1=\frac{0.2\times119.4}{45} \\ C_1=\frac{23.88}{45} \\ C_1=0.53M \end{gathered}[/tex]

Hence the molarity of the nitric acid is 0.53L