LynnleaC455863 LynnleaC455863
  • 03-11-2022
  • Physics
contestada

After traveling for 6.0 seconds, a runner reaches a speed of 12 m/s after startingfrom rest. What is the runner's acceleration?

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AmeirF489504 AmeirF489504
  • 03-11-2022

Given data:

Initial speed of the runner as he starts from the rest;

[tex]u=0[/tex]

Final speed of the runner;

[tex]v=12\text{ m/s}[/tex]

Time taken;

[tex]t=6.0\text{ s}[/tex]

The acceleration of the runner is given as,

[tex]a=\frac{v-u}{t}[/tex]

Substituting all known values,

[tex]\begin{gathered} a=\frac{(12\text{ m/s})-0}{(6.0\text{ s})} \\ =2\text{ m/s}^2 \end{gathered}[/tex]

Therefore, the acceleration of the runner is 2 m/s².

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