Ashelton27 Ashelton27

02-03-2017
Mathematics

contestada

if the perimeter of the rectangle is 32cm and the area is 55cm2, what are the dimensions of the rectangle?

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wolf1728 wolf1728

03-03-2017

2L + 2W = 32
L * W = 55

L = 55/W then substitute into first equation
2 * 55/W + 2W = 32 Multiplying both sides by "W"
110 + 2W^2 = 32 W
2W^2 -32W +110 = 0
L = 11 or L = 5
Also W = 11 or W = 5

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