Funky666000 Funky666000
  • 02-05-2017
  • Mathematics
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How do I solve 2cos(x)=2sin(2x)

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dmisael
dmisael dmisael
  • 03-05-2017
2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
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