The possible values of x are given by x−3≥2 . What is the least possible value of 5x ?

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03-05-2017
Mathematics

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The possible values of x are given by x−3≥2 . What is the least possible value of 5x ?

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All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

ellabakker2 ellabakker2 · Answer 1 · 2017-05-03T02:52:40+02:00

ellabakker2 ellabakker2

03-05-2017

x has to be higher than 1. 5-3 is 2, which is equal to two but not greater than. X cannot be less than 1. To show this in an inequality:

x[tex] \geq [/tex]1

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FadaKen FadaKen · Answer 2 · 2017-05-03T02:59:27+02:00

FadaKen FadaKen

03-05-2017

[tex] x-3\geq2 implies x \geq 3+2 hence x \geq 5 [/tex].

this means x has smallest value 5.

THE SMALLEST VALUE OF 5X will thus be 5 * 5 = 25

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