benharrigan04
benharrigan04 benharrigan04
  • 04-03-2018
  • Mathematics
contestada

[tex] \frac{2[tex]\sqrt{3} [/tex]}{3[tex]\sqrt{5} [/tex]} [/tex]

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Аноним Аноним
  • 04-03-2018
We have to rationalize the denominator and then, if we can, simplify.

I have to multiply for 1 but I write it [tex] \frac{ \sqrt{5} }{ \sqrt{5} } [/tex]

So [tex] \frac{2 \sqrt{3} }{3 \sqrt{5} }* \frac{ \sqrt{5} }{ \sqrt{5} } [/tex] = [tex] \frac{2 \sqrt{3} * \sqrt{5} }{3*5}[/tex]

Final result = [tex] \frac{2 \sqrt{15} }{15}[/tex]
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